### Video Transcript

Make π₯ the subject of the equation π¦ equals two to the ππ₯ plus π power, assuming that π does not equal zero.

We can go from exponential form to logarithmic form, π to the π₯ power equals π. So taking our equation and using the same circle method, two to the ππ₯ plus π equals π¦. Now letβs solve for π₯. Letβs subtract π and then divide by π. So weβve subtracted π and now divide both sides by π.

Therefore, log base two of π¦ minus π divided by π is equal to π₯.